Optimal. Leaf size=170 \[ \frac{2 b g \sqrt{g \sec (e+f x)} \sqrt{\frac{a \cos (e+f x)+b}{a+b}} \Pi \left (2;\frac{1}{2} (e+f x)|\frac{2 a}{a+b}\right )}{d f \sqrt{a+b \sec (e+f x)}}-\frac{2 g (b c-a d) \sqrt{g \sec (e+f x)} \sqrt{\frac{a \cos (e+f x)+b}{a+b}} \Pi \left (\frac{2 c}{c+d};\frac{1}{2} (e+f x)|\frac{2 a}{a+b}\right )}{d f (c+d) \sqrt{a+b \sec (e+f x)}} \]
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Rubi [A] time = 0.842811, antiderivative size = 170, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 39, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.128, Rules used = {3971, 3859, 2807, 2805, 3975} \[ \frac{2 b g \sqrt{g \sec (e+f x)} \sqrt{\frac{a \cos (e+f x)+b}{a+b}} \Pi \left (2;\frac{1}{2} (e+f x)|\frac{2 a}{a+b}\right )}{d f \sqrt{a+b \sec (e+f x)}}-\frac{2 g (b c-a d) \sqrt{g \sec (e+f x)} \sqrt{\frac{a \cos (e+f x)+b}{a+b}} \Pi \left (\frac{2 c}{c+d};\frac{1}{2} (e+f x)|\frac{2 a}{a+b}\right )}{d f (c+d) \sqrt{a+b \sec (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 3971
Rule 3859
Rule 2807
Rule 2805
Rule 3975
Rubi steps
\begin{align*} \int \frac{(g \sec (e+f x))^{3/2} \sqrt{a+b \sec (e+f x)}}{c+d \sec (e+f x)} \, dx &=\frac{b \int \frac{(g \sec (e+f x))^{3/2}}{\sqrt{a+b \sec (e+f x)}} \, dx}{d}-\frac{(b c-a d) \int \frac{(g \sec (e+f x))^{3/2}}{\sqrt{a+b \sec (e+f x)} (c+d \sec (e+f x))} \, dx}{d}\\ &=\frac{\left (b g \sqrt{b+a \cos (e+f x)} \sqrt{g \sec (e+f x)}\right ) \int \frac{\sec (e+f x)}{\sqrt{b+a \cos (e+f x)}} \, dx}{d \sqrt{a+b \sec (e+f x)}}-\frac{\left ((b c-a d) g \sqrt{b+a \cos (e+f x)} \sqrt{g \sec (e+f x)}\right ) \int \frac{1}{\sqrt{b+a \cos (e+f x)} (d+c \cos (e+f x))} \, dx}{d \sqrt{a+b \sec (e+f x)}}\\ &=\frac{\left (b g \sqrt{\frac{b+a \cos (e+f x)}{a+b}} \sqrt{g \sec (e+f x)}\right ) \int \frac{\sec (e+f x)}{\sqrt{\frac{b}{a+b}+\frac{a \cos (e+f x)}{a+b}}} \, dx}{d \sqrt{a+b \sec (e+f x)}}-\frac{\left ((b c-a d) g \sqrt{\frac{b+a \cos (e+f x)}{a+b}} \sqrt{g \sec (e+f x)}\right ) \int \frac{1}{\sqrt{\frac{b}{a+b}+\frac{a \cos (e+f x)}{a+b}} (d+c \cos (e+f x))} \, dx}{d \sqrt{a+b \sec (e+f x)}}\\ &=\frac{2 b g \sqrt{\frac{b+a \cos (e+f x)}{a+b}} \Pi \left (2;\frac{1}{2} (e+f x)|\frac{2 a}{a+b}\right ) \sqrt{g \sec (e+f x)}}{d f \sqrt{a+b \sec (e+f x)}}-\frac{2 (b c-a d) g \sqrt{\frac{b+a \cos (e+f x)}{a+b}} \Pi \left (\frac{2 c}{c+d};\frac{1}{2} (e+f x)|\frac{2 a}{a+b}\right ) \sqrt{g \sec (e+f x)}}{d (c+d) f \sqrt{a+b \sec (e+f x)}}\\ \end{align*}
Mathematica [C] time = 3.82805, size = 223, normalized size = 1.31 \[ -\frac{2 i g \cot (e+f x) \sqrt{g \sec (e+f x)} \sqrt{-\frac{a (\cos (e+f x)-1)}{a+b}} \sqrt{\frac{a (\cos (e+f x)+1)}{a-b}} \sqrt{a+b \sec (e+f x)} \left (\Pi \left (1-\frac{a}{b};i \sinh ^{-1}\left (\sqrt{\frac{1}{a-b}} \sqrt{b+a \cos (e+f x)}\right )|\frac{b-a}{a+b}\right )-\Pi \left (\frac{(a-b) c}{a d-b c};i \sinh ^{-1}\left (\sqrt{\frac{1}{a-b}} \sqrt{b+a \cos (e+f x)}\right )|\frac{b-a}{a+b}\right )\right )}{d f \sqrt{\frac{1}{a-b}} \sqrt{a \cos (e+f x)+b}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.391, size = 465, normalized size = 2.7 \begin{align*}{\frac{-2\,i \left ( \cos \left ( fx+e \right ) \right ) ^{2}}{fd \left ( c+d \right ) \left ( c-d \right ) \left ( a\cos \left ( fx+e \right ) +b \right ) }\sqrt{{\frac{a\cos \left ( fx+e \right ) +b}{ \left ( a+b \right ) \left ( 1+\cos \left ( fx+e \right ) \right ) }}} \left ({\it EllipticF} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},\sqrt{-{\frac{a-b}{a+b}}} \right ) acd+{\it EllipticF} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},\sqrt{-{\frac{a-b}{a+b}}} \right ) a{d}^{2}-{\it EllipticF} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},\sqrt{-{\frac{a-b}{a+b}}} \right ) bcd-{\it EllipticF} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},\sqrt{-{\frac{a-b}{a+b}}} \right ) b{d}^{2}-2\,{\it EllipticPi} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},-1,i\sqrt{{\frac{a-b}{a+b}}} \right ) b{c}^{2}+2\,{\it EllipticPi} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},-1,i\sqrt{{\frac{a-b}{a+b}}} \right ) b{d}^{2}-2\,{\it EllipticPi} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},-{\frac{c-d}{c+d}},i\sqrt{{\frac{a-b}{a+b}}} \right ) acd+2\,{\it EllipticPi} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},-{\frac{c-d}{c+d}},i\sqrt{{\frac{a-b}{a+b}}} \right ) b{c}^{2} \right ) \sqrt{{\frac{a\cos \left ( fx+e \right ) +b}{\cos \left ( fx+e \right ) }}} \left ({\frac{g}{\cos \left ( fx+e \right ) }} \right ) ^{{\frac{3}{2}}}{\frac{1}{\sqrt{ \left ( 1+\cos \left ( fx+e \right ) \right ) ^{-1}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{b \sec \left (f x + e\right ) + a} \left (g \sec \left (f x + e\right )\right )^{\frac{3}{2}}}{d \sec \left (f x + e\right ) + c}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{b \sec \left (f x + e\right ) + a} \left (g \sec \left (f x + e\right )\right )^{\frac{3}{2}}}{d \sec \left (f x + e\right ) + c}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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